Description

Ice must be of a certain thickness to safely bear a given weight under ideal conditions. The ice may need to be much thicker if it is weak.


 

thickness of ice in inches =

= 4 * SQRT(weight of load in tons)

 

where:

• 1 ton is 2,000 lbs in the U.S.

 

If the load to ice thickness diagram (log-log plot) is modeled in Minitab:

 

thickness in inches =

= (3.749 * ((LOG10(tons))^3)) - (1.909 * ((LOG10(tons))^2)) + (6.732 * LOG10(tons)) + 3.836

 

When conditions are not ideal or the ice is weak then the rice may need to be 2 to 3 times thicker.

 


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