Description

Morey and McAninch evaluated stenotic lesions in the anterior urethra of males using ultrasonography. They used this information to estimate the size of a flap width needed to create a neourethra for the patient. The authors are from the University of California at San Francisco and Brooke Army Medical Center at Fort Sam Houston in Texas.


 

The French size of a catheter is 3 times the external diameter in mm (see Chapter 40).

 

To prepare a neourethra with a 26 French size a quick estimate is:

 

flap width required in mm =

= 26 - (3 * (diameter of stenotic urethra in mm)) =

= 26 - (French size of stenotic urthra)

 

This appears to generalize to:

 

flap width required in mm =

= (desired French size) - (3 * (diameter of stenotic urethra in mm)) =

= (desired French size) - (French size of stenotic urthra)

 

To be precise:

 

desired circumference in mm =

= (desired French) / 3 * PI()

 

flap size needed in mm =

= ((desired French) / 3 * PI()) - ((diameter in mm) * PI())

 

The quick estimate appears to underestimate the precise calculation by less than 1 mm over much of the French range.

 


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