Subject: fetal long bones
Parameters:
(1) length of humerus in mm
(2) length of ulna in mm
(3) length of radius in mm
(4) length of femur in mm
(5) length of tibia in mm
(6) length of fibula in mm
mean age based on humerus =
= 54.8143 – (14.2856 * SQRT(10.7761 – (0.14 * (length of humerus))))
standard deviation for age based on humerus =
= (1.99 * 1.04 * SQRT(1.01 + ((((length of humerus) – 32.57)^2) / 21470.96)))
mean age based on ulna =
= 50.8026 – (13.1578 * SQRT(10.4394 – (0.152 * (length of ulna))))
standard deviation for age based on ulna =
= (1.99 * 1.14 * SQRT(1.01 + ((((length of ulna) – 30.79)^2) / 18684.28)))
mean age based on radius =
= 48.2143 – (14.2857 * SQRT(7.9280 – (0.14 * (length of radius))))
standard deviation for age based on radius =
= (1.99 * 1.30 * SQRT(1.01 + ((((length of radius) – 27.6)^2) / 11902.86)))
mean age based on femur =
= 66.1613 – (16.129 * SQRT(12.7263 – (0.124 * (length of femur))))
standard deviation for age based on femur =
= (1.99 * SQRT(1.01 + ((((length of femur) – 34.46)^2) / 31349.94)))
mean age based on tibia =
= 68.1538 – (19.2308 * SQRT(9.5198 – (0.104 * (length of tibia))))
standard deviation for age based on tibia =
= (1.99 * 1.14 * SQRT(1.01 + ((((length of tibia) – 30.14)^2) / 22522.5)))
mean age based on fibula =
= 66.8966 – (17.2414 * SQRT(9.3665 – (0.116 * (length of fibula))))
standard deviation for age based on fibula =
= (1.99 * 1.08 * SQRT(1.01 + ((((length of fibula) – 30.16)^2) / 17230.4)))
