Description

Chen et al used flaccid and stretched penile lengths to predict erect size. This can avoid the need for intracavernosal injections. The authors are from Tel Aviv-Sourasky Medical Center and Tel Aviv University.


 

Measurements:

(1) dorsal length: from the pubo-penile angle to the urethral meatus (proximal end at the pubic bone to reduce effect of prepubic fat pad)

(2) ventral length: from the peno-scrotal angle to the urethral meatus

 

ratio of stretched to flaccid length =

= (stretched penile length in cm) / (flaccid penile length in cm)

 

ratio of erectile to flaccid length =

= (erected penile length in cm) / (flaccid penile length in cm)

 

ratio of ventral erectile to flaccid length =

= (1.113 * (ratio of ventral stretched to flaccid lengths)) - 0.031

 

ratio of dorsal erectile to flaccid length =

= (0.849 * (ratio of dorsal stretched to flaccid lengths)) + 0.3657

 

where:

• R squared for the ventral equation = 0.76 and for the dorsal equation = 0.48

• The end point for stretching was onset of patient discomfort.

• Ventral means near the abdomen and dorsal towards the back (or underside of a leave in Botany). I would have thought the aspect terms would have been reversed.

 

If this equation is expanded based on the definition of the ratios:

 

ventral length erected in cm =

= (1.113 * (ventral length of penis stretched in cm)) - (0.031 * (ventral flaccid length in cm))

 

dorsal length erected in cm =

= (0.849 * (dorsal length of penis stretched in cm)) + (0.3657 * (dorsal flaccid length in cm))

 

The correlation between the stretched and erect lengths is affected by:

(1) penile elasticity (which is greater in younger men)

(2) the force used on stretching

 

Based on engineerng analysis the authors found that the stretched length using a force of 450 grams (4.41 Newtons) approximated the erected length. Most of the time stretching is done with a much lower force because of patient discomfort. The recommendation was to use a standard stretching pressure to reduce variability in the readings.

 

where:

• 1 Newton = 101.97 grams

 


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