Description

An updated coronary risk profile based on the Framingham data can be used to assess the risk of a patient for coronary heart disease (CHD).


 

age range: persons from ages 30-74

 

Parameter

Finding

Points

smoking

is a current smoker or quit within past year

1

 

otherwise

0

diabetes

treatment with insulin or oral agent or having a fasting glucose >= 140 mg/dL

1

 

otherwise

0

left ventricular hypertrophy on ECG

evidence of left ventricular hypertrophy

1

 

no evidence of left ventricular hypertrophy

0

 

If parameter data is not available, then it is assumed negative.

 

Using the Systolic Blood Pressure

 

The systolic blood pressure is the average of 2 office measurements.

 

a value =

= 11.1122 - (0.9119 * (LN(systolic blood pressure))) - (0.2767 * (smoking points)) - (0.7181 * (LN((total cholesterol in mg/dL) / (HDL cholesterol in mg/dL)))) - (0.5865 * (left ventricular hypertrophy points))

 

m value for men =

= (a value) - (1.4792 * (LN(age in years))) - (0.1759 * (diabetes points))

 

m value for women

= (a value) - 5.8549 + (1.8515 * ((LN((age in years) / 74)) ^ 2)) - (0.3758 * (diabetes points))

 

µ value =

= 4.4181+ (m value)

 

sigma value =

= EXP(-0.3155 - (0.2784 * (m value)))

 

Using the Diastolic Blood Pressure

 

The diastolic blood pressure is the average of 2 office measurements.

 

a value =

= 11.0938 - (0.867 * (LN(diastolic blood pressure))) - (0.2789 * (smoking points)) - (0.7142 * (LN((total cholesterol in mg/dL) / (HDL cholesterol in mg/dL)))) - (0.7195 * (left ventricular hypertrophy points))

 

m value for men =

= (a value) - (1.6346 * (LN(age in years))) - (0.2082* (diabetes points))

 

m value for women

= (a value) - 6.5306+ (2.1059 * ((LN((age in years) / 74)) ^ 2)) - (0.4055* (diabetes points))

 

µ value =

= 4.4284+ (m value)

 

sigma value =

= EXP(-0.3171 - (0.2825 * (m value)))

 

Predicted Probability of Coronary Heart Disease

 

u value =

= (LN(time interval in years) - (µ value)) / (sigma value)

 

where

• time interval is usually 5 or 10 years

 

predicted probability for time interval =

= 1 - EXP((-1) * EXP(u value))

 


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